$BR^3_{1}\quad U=\iota\quad D=\iota\quad \hbox{order 2} \quad S, c_1 = 6, c_2 = 0$\hfil\break $BR^3_{2}\quad U=(\iota , (2 3) , (2 3))\quad D=(\iota , (2 3) , (2 3))\quad \hbox{order 2} \quad S, c_1 = 2, c_2 = 0$\hfil\break $BR^3_{3}\quad U=(\iota , (2 3) , (2 3))\quad D=((2 3) , \iota , \iota)\quad \hbox{order 4} \quad c_1 = 2, c_2 = 0$\hfil\break $BR^3_{4}\quad U=(\iota , (2 3) , (2 3))\quad D=((2 3) , (2 3) , (2 3))\quad \hbox{order 4} \quad c_1 = 4, c_2 = 2$\hfil\break $BR^3_{5}\quad U=(\iota , (1 3 2) , (1 2 3))\quad D=((2 3) , (2 3) , (2 3))\quad \hbox{order 3} \quad c_1 = 3, c_2 = 3$\hfil\break $BR^3_{6}\quad U=(\iota , \iota , (1 2))\quad D=(\iota , \iota , (1 2))\quad \hbox{order 2} \quad S, c_1 = 2, c_2 = 0$\hfil\break $BR^3_{7}\quad U=((2 3) , \iota , \iota)\quad D=\iota\quad \hbox{order 4} \quad c_1 = 4, c_2 = 2$\hfil\break $BR^3_{8}\quad U=((2 3) , \iota , \iota)\quad D=((2 3) , (2 3) , (2 3))\quad \hbox{order 4} \quad c_1 = 4, c_2 = 2$\hfil\break $BR^3_{9}\quad U=((2 3) , (2 3) , (2 3))\quad D=((2 3) , (2 3) , (2 3))\quad \hbox{order 2} \quad S, c_1 = 6, c_2 = 0$\hfil\break $BR^3_{10}\quad U=((2 3) , (1 3) , (1 2))\quad D=\iota\quad \hbox{order 3} \quad c_1 = 3, c_2 = 3$\hfil\break $BR^3_{11}\quad U=((1 2) , (2 3) , (1 3))\quad D=((1 2 3) , (1 2 3) , (1 2 3))\quad \hbox{order 3} \quad c_1 = 3, c_2 = 3$\hfil\break $BR^3_{12}\quad U=((1 2 3) , (1 2 3) , (1 2 3))\quad D=((1 2 3) , (1 2 3) , (1 2 3))\quad \hbox{order 6} \quad S, c_1 = 6, c_2 = 0$\hfil\break $BR^3_{13}\quad U=((1 2 3) , (1 2 3) , (1 2 3))\quad D=((1 3 2) , (1 3 2) , (1 3 2))\quad \hbox{order 2} \quad c_1 = 6, c_2 = 0$\hfil\break $BR^3_{14}\quad U=((1 3 2) , (1 3 2) , (1 3 2))\quad D=\iota\quad \hbox{order 6} \quad c_1 = 6, c_2 = 0$\hfil\break $BR^3_{15}\quad U=((1 3) , \iota , (1 3))\quad D=\iota\quad \hbox{order 4} \quad c_1 = 4, c_2 = 2$\hfil\break $BR^3_{16}\quad U=((1 3) , (1 3) , (1 3))\quad D=\iota\quad \hbox{order 4} \quad c_1 = 6, c_2 = 0$\hfil\break